What is the solution for y^{''}-7y^'+6y=0,y(0)=0,y^'(0)=0 ?

The solution for y^{''}-7y^'+6y=0,y(0)=0,y^'(0)=0 is y=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-7y^'+6y=0,y(0)=0,y^'(0)=0

y^{^{''}} - 7 y^{^{'}} + 6 y = 0, y (0) = 0, y^{^{'}} (0) = 0

y = 0

Solution steps

y^{''} (t) - 7 y^{'} (t) + 6 y = 0

Solve linear ODE:

y = 0

y = 0

\frac{d}{d x} (\frac{1}{8} x 64 - x^{2})

(5, - 4), (4, 7)

\int \frac{7}{x 36 - 49 ln ^{2} ( x )} d x

\frac{d}{d x} (x sin (x) + cos (x))

\int 1 - cos (t) d t

What is the solution for y^{''}-7y^'+6y=0,y(0)=0,y^'(0)=0 ?
The solution for y^{''}-7y^'+6y=0,y(0)=0,y^'(0)=0 is y=0