What is the derivative of-0.025x^2+9x ?

The derivative of-0.025x^2+9x is -0.05x+9

What is the first derivative of-0.025x^2+9x ?

The first derivative of-0.025x^2+9x is -0.05x+9

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\frac{d}{d x} (- 0.025 x^{2} + 9 x)

- 0.05 x + 9

Solution steps

\frac{d}{d x} (- 0.025 x^{2} + 9 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (0.025 x^{2}) + \frac{d}{d x} (9 x)

\frac{d}{d x} (0.025 x^{2}) = 0.05 x

\frac{d}{d x} (9 x) = 9

= - 0.05 x + 9

\frac{7}{2 7 x + 2}, at a = 2

\int x csc^{2} (x) d x

(x + 2 y^{2}) d x + (x y) d y = 0

\int (x + 20) 40 x + x^{2} d x

\int cos (\frac{2 πn x}{L}) d x

What is the derivative of-0.025x^2+9x ?
The derivative of-0.025x^2+9x is -0.05x+9
What is the first derivative of-0.025x^2+9x ?
The first derivative of-0.025x^2+9x is -0.05x+9