What is the derivative of e^{ln(x^2}) ?

The derivative of e^{ln(x^2}) is 2x

What is the first derivative of e^{ln(x^2}) ?

The first derivative of e^{ln(x^2}) is 2x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (e^{l n (x^{2})})

2 x

Solution steps

\frac{d}{d x} (e^{l n (x^{2})})

Simplify

e^{l n (x^{2})} : x^{2}

= \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 x^{2 - 1}

Simplify

= 2 x

x \to 0 lim (\frac{1}{x ^{3}})

\frac{d}{d x} (\frac{x}{( 1 - x ) ^{2}})

f (x) = \frac{7}{r ^{3}}

\int \frac{cos ( x )}{1 + 7 sin ( x )} d x

\int cos (x^{4}) d x

What is the derivative of e^{ln(x^2}) ?
The derivative of e^{ln(x^2}) is 2x
What is the first derivative of e^{ln(x^2}) ?
The first derivative of e^{ln(x^2}) is 2x