What is (\partial)/(\partial x)(3x^3+x^2y-3y^3) ?

The answer to (\partial)/(\partial x)(3x^3+x^2y-3y^3) is 9x^2+2xy

Popular >

(\partial)/(\partial x)(3x^3+x^2y-3y^3)

\frac{\partial}{\partial x} (3 x^{3} + x^{2} y - 3 y^{3})

9 x^{2} + 2 x y

Solution steps

\frac{\partial}{\partial x} (3 x^{3} + x^{2} y - 3 y^{3})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{3}) + \frac{\partial}{\partial x} (x^{2} y) - \frac{\partial}{\partial x} (3 y^{3})

\frac{\partial}{\partial x} (3 x^{3}) = 9 x^{2}

\frac{\partial}{\partial x} (x^{2} y) = 2 y x

\frac{\partial}{\partial x} (3 y^{3}) = 0

= 9 x^{2} + 2 y x - 0

Simplify

= 9 x^{2} + 2 x y

a x^{2}

\int 13 x^{2} sin (π x) d x

y = 10 x - x + 3, (100, 3)

\int_{0}^{10} 2 π y (100 - y^{2}) d y

\int x^{2} 0. 4^{- x} x d x

What is (\partial)/(\partial x)(3x^3+x^2y-3y^3) ?
The answer to (\partial)/(\partial x)(3x^3+x^2y-3y^3) is 9x^2+2xy