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Popular >

y^{''}+2t=0

Solution

y^{^{''}} + 2 t = 0

Solution

y = - \frac{t ^{3}}{3} + c_{1} t + c_{2}

Solution steps

y^{''} (t) + 2 t = 0

Isolate

y^{''} (t) : y^{''} (t) = - 2 t

Solve

y^{''} (t) = - 2 t : y^{'} (t) = - t^{2} + c_{1}

Solve

y^{'} (t) = - t^{2} + c_{1} : y = - \frac{t ^{3}}{3} + c_{1} t + c_{2}

y = - \frac{t ^{3}}{3} + c_{1} t + c_{2}

Popular Examples

integral from-1 to 2 of-x^2+x+2

\int_{- 1}^{2} - x^{2} + x + 2 d x

integral of 1/((x^2+36)^{3/2)}

\int \frac{1}{( x ^{2} + 36 ) ^{\frac{3}{2}}} d x

(\partial)/(\partial y)((t^2+y^2)^{3/2})

\frac{\partial}{\partial y} ((t^{2} + y^{2})^{\frac{3}{2}})

tangent of f(x)=(2x+4)^{1/5},\at x=1 tangent of

f (x) = (2 x + 4)^{\frac{1}{5}}, at x = 1

limit as y approaches infinity of ((y^2-e^{(6y)}))/((4y^2+e^{7y))}

y \to \infty lim (\frac{( y ^{2} - e ^{(6 y)} )}{( 4 y ^{2} + e ^{7 y} )})

Frequently Asked Questions (FAQ)

What is the solution for y^{''}+2t=0 ?
The solution for y^{''}+2t=0 is y=-(t^3)/3+c_{1}t+c_{2}