What is (\partial)/(\partial y)(4x^3y^3+1) ?

The answer to (\partial)/(\partial y)(4x^3y^3+1) is 12x^3y^2

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(\partial)/(\partial y)(4x^3y^3+1)

\frac{\partial}{\partial y} (4 x^{3} y^{3} + 1)

12 x^{3} y^{2}

Solution steps

\frac{\partial}{\partial y} (4 x^{3} y^{3} + 1)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (4 x^{3} y^{3}) + \frac{\partial}{\partial y} (1)

\frac{\partial}{\partial y} (4 x^{3} y^{3}) = 12 x^{3} y^{2}

\frac{\partial}{\partial y} (1) = 0

= 12 x^{3} y^{2} + 0

Simplify

= 12 x^{3} y^{2}

n = 0 \sum \infty 0. 1^{n}

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What is (\partial)/(\partial y)(4x^3y^3+1) ?
The answer to (\partial)/(\partial y)(4x^3y^3+1) is 12x^3y^2