What is the derivative of 6+3x-4x(7x+1^2) ?

The derivative of 6+3x-4x(7x+1^2) is -588x^2-112x-1

What is the first derivative of 6+3x-4x(7x+1^2) ?

The first derivative of 6+3x-4x(7x+1^2) is -588x^2-112x-1

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\frac{d}{d x} (6 + 3 x - 4 x (7 x + 1)^{2})

- 588 x^{2} - 112 x - 1

Solution steps

\frac{d}{d x} (6 + 3 x - 4 x (7 x + 1)^{2})

Simplify

6 + 3 x - 4 x (7 x + 1)^{2} : - 196 x^{3} - 56 x^{2} - x + 6

= \frac{d}{d x} (- 196 x^{3} - 56 x^{2} - x + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (196 x^{3}) - \frac{d}{d x} (56 x^{2}) - \frac{d x}{d x} + \frac{d}{d x} (6)

\frac{d}{d x} (196 x^{3}) = 588 x^{2}

\frac{d}{d x} (56 x^{2}) = 112 x

\frac{d x}{d x} = 1

\frac{d}{d x} (6) = 0

= - 588 x^{2} - 112 x - 1 + 0

Simplify

= - 588 x^{2} - 112 x - 1

\int 6 x^{4} - 6 x^{3} + 4 x^{2} + C d x

\frac{\partial}{\partial x} (2 x y ln (x))

\frac{\partial}{\partial t} (sin (2 x) cos (2 t))

\int (6 x^{2} + 2 x - 1) d x

What is the derivative of 6+3x-4x(7x+1^2) ?
The derivative of 6+3x-4x(7x+1^2) is -588x^2-112x-1
What is the first derivative of 6+3x-4x(7x+1^2) ?
The first derivative of 6+3x-4x(7x+1^2) is -588x^2-112x-1