What is (\partial)/(\partial x)((x-6)(y+4)) ?

The answer to (\partial)/(\partial x)((x-6)(y+4)) is y+4

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(\partial)/(\partial x)((x-6)(y+4))

\frac{\partial}{\partial x} ((x - 6) (y + 4))

y + 4

Solution steps

\frac{\partial}{\partial x} ((x - 6) (y + 4))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (y + 4) \frac{\partial}{\partial x} (x - 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= (y + 4) (\frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (6))

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (6) = 0

= (y + 4) (1 - 0)

Simplify

= y + 4

\frac{d}{d x} (\frac{8 x}{7 - tan ( x )})

\frac{d y}{d t} = - 2 t y + 4 e^{- t^{2}}

\frac{d}{d x} (x^{\frac{2}{3}} (\frac{5}{2} - x))

\frac{2 x + 3}{3 x - 2}

sin (9 x) sin (2 x)

What is (\partial)/(\partial x)((x-6)(y+4)) ?
The answer to (\partial)/(\partial x)((x-6)(y+4)) is y+4