What is the integral of (-9cos(x)) ?

The integral of (-9cos(x)) is -9sin(x)+C

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integral of (-9cos(x))

\int (- 9 cos (x)) d x

- 9 sin (x) + C

Solution steps

\int - 9 cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 9 \cdot \int cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= - 9 sin (x)

Add a constant to the solution

= - 9 sin (x) + C

\int x^{2} - 9 x + 14 d x

\int \frac{x + 2}{x ^{2} + 5 x} d x

\frac{d y}{d x} = 5 x - y

\int_{0}^{6} 2 e^{x} d x

\frac{1}{s ( s + 2 ) ( s + 3 )}