What is the derivative of tan(x^2-9) ?

The derivative of tan(x^2-9) is sec^2(x^2-9)*2x

What is the first derivative of tan(x^2-9) ?

The first derivative of tan(x^2-9) is sec^2(x^2-9)*2x

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\frac{d}{d x} (tan (x^{2} - 9))

sec^{2} (x^{2} - 9) \cdot 2 x

Solution steps

\frac{d}{d x} (tan (x^{2} - 9))

Apply the chain rule:

sec^{2} (x^{2} - 9) \frac{d}{d x} (x^{2} - 9)

= sec^{2} (x^{2} - 9) \frac{d}{d x} (x^{2} - 9)

\frac{d}{d x} (x^{2} - 9) = 2 x

= sec^{2} (x^{2} - 9) \cdot 2 x

\int cos (ln (x^{2})) d x

\int \frac{x ^{2}}{2 x ^{3} + 1} d x

f (x) = \frac{6}{x}, at x = 4

3 y^{^{'}} + 5 y = 1

\int 2 sin (\frac{t}{2}) d t

What is the derivative of tan(x^2-9) ?
The derivative of tan(x^2-9) is sec^2(x^2-9)*2x
What is the first derivative of tan(x^2-9) ?
The first derivative of tan(x^2-9) is sec^2(x^2-9)*2x