What is the solution for xy^'=y+sqrt(x^2-y^2) ?

The solution for xy^'=y+sqrt(x^2-y^2) is y=sin(ln(x)+c_{1})x

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xy^'=y+sqrt(x^2-y^2)

x y^{^{'}} = y + x^{2} - y^{2}

y = sin (ln (x) + c_{1}) x

Solution steps

x y^{'} (x) = y + x^{2} - y^{2}

Solve using substitution:

y = sin (ln (x) + c_{1}) x

y = sin (ln (x) + c_{1}) x

x \to 1 - lim (\frac{5}{x ^{3} - 1})

f (x) = 4 x^{2} - 2 x + 1, at x = 3

1 + e^{x}

\int - x cos (2 x) d x

e^{4 x^{2} + 1}

What is the solution for xy^'=y+sqrt(x^2-y^2) ?
The solution for xy^'=y+sqrt(x^2-y^2) is y=sin(ln(x)+c_{1})x