What is the tangent of y=sqrt(3x),(3,3) ?

The tangent of y=sqrt(3x),(3,3) is y= 1/2 x+3/2

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tangent of y=sqrt(3x),(3,3)

tangent of

y = 3 x, (3, 3)

y = \frac{1}{2} x + \frac{3}{2}

Solution steps

Find the slope of

y = 3 x : \frac{d y}{d x} = \frac{3}{2 x}

Compute the slope of

y = 3 x

(3, 3) : m = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(3, 3) : y = \frac{1}{2} x + \frac{3}{2}

y = \frac{1}{2} x + \frac{3}{2}

\int e^{6 - 5 t} d t

\int x sin (3 t - 3 x) d x

\frac{\partial}{\partial y} (3 x + 2 y)

\frac{d}{d x} (\frac{8 + x f ( x )}{x})

\int sin (x) \frac{1}{x} d x

What is the tangent of y=sqrt(3x),(3,3) ?
The tangent of y=sqrt(3x),(3,3) is y= 1/2 x+3/2