What is the integral of (ln(x))/(16) ?

The integral of (ln(x))/(16) is 1/16 (xln(x)-x)+C

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integral of (ln(x))/(16)

\int \frac{ln ( x )}{16} d x

\frac{1}{16} (x ln (x) - x) + C

Solution steps

\int \frac{ln ( x )}{16} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{16} \cdot \int ln (x) d x

Apply Integration By Parts

: x ln (x) - \int 1 d x

= \frac{1}{16} (x ln (x) - \int 1 d x)

\int 1 d x = x

= \frac{1}{16} (x ln (x) - x)

Add a constant to the solution

= \frac{1}{16} (x ln (x) - x) + C

\frac{d}{d x} ((3 - 4 x) e^{- 2 x^{2}})

\frac{d}{d x} (\frac{x ^{3} - 3 x ^{2} + 4 x - 5}{x ^{2}})

x \to - \infty lim (8^{x})

n \to \infty lim \frac{( ( n + 1 ) ^{3} )}{5 ^{n + 1}}

x^{2} y^{^{''}} + 5 x y^{^{'}} + 3 y = 0

What is the integral of (ln(x))/(16) ?
The integral of (ln(x))/(16) is 1/16 (xln(x)-x)+C