What is the tangent of y=3x^3-2x,(-1,-1) ?

The tangent of y=3x^3-2x,(-1,-1) is y=7x+6

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tangent of y=3x^3-2x,(-1,-1)

tangent of

y = 3 x^{3} - 2 x, (- 1, - 1)

y = 7 x + 6

Solution steps

Find the slope of

y = 3 x^{3} - 2 x : \frac{d y}{d x} = 9 x^{2} - 2

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 7

Find the line with slope m=

7

and passing through

(- 1, - 1) : y = 7 x + 6

y = 7 x + 6

\int - 0.2 x + 43 d x

\frac{7 + 2 x}{9 - 8 x}

\frac{d}{d x} ((4 + 3 x)^{2})

\int 15 e^{- 5 x} d x

\int 200 d x

What is the tangent of y=3x^3-2x,(-1,-1) ?
The tangent of y=3x^3-2x,(-1,-1) is y=7x+6