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Popular >

y^{''}-2y^'=e^x

Solution

y^{^{''}} - 2 y^{^{'}} = e^{x}

Solution

y = c_{1} e^{2 x} + c_{2} - e^{x}

Solution steps

y^{''} (x) - 2 y^{'} (x) = e^{x}

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} - e^{x}

y = c_{1} e^{2 x} + c_{2} - e^{x}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^{''}-2y^'=e^x ?
The solution for y^{''}-2y^'=e^x is y=c_{1}e^{2x}+c_{2}-e^x