What is the first derivative of 2+3x ?

The first derivative of 2+3x is 3

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derivative of 2+3x

\frac{d}{d x} (2 + 3 x)

3

Solution steps

\frac{d}{d x} (2 + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) + \frac{d}{d x} (3 x)

\frac{d}{d x} (2) = 0

\frac{d}{d x} (3 x) = 3

= 0 + 3

Simplify

= 3

- 2 x^{2} + 8, 3 x + 1, 0

\int (x^{2} - 7 x + 4) d x

y^{^{''}} + 4 y^{^{'}} + 4 y = (5 + x) e^{- 2 x}

\frac{d y}{d x} + \frac{y}{x} = e^{x}

\frac{d}{d x} (d - b + \frac{- a x ^{3} - d}{x ^{2}})