What is the derivative of e^{2x}+e^{-3x} ?

The derivative of e^{2x}+e^{-3x} is e^{2x}*2-3e^{-3x}

What is the first derivative of e^{2x}+e^{-3x} ?

The first derivative of e^{2x}+e^{-3x} is e^{2x}*2-3e^{-3x}

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\frac{d}{d x} (e^{2 x} + e^{- 3 x})

e^{2 x} \cdot 2 - 3 e^{- 3 x}

Solution steps

\frac{d}{d x} (e^{2 x} + e^{- 3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{2 x}) + \frac{d}{d x} (e^{- 3 x})

\frac{d}{d x} (e^{2 x}) = e^{2 x} \cdot 2

\frac{d}{d x} (e^{- 3 x}) = - 3 e^{- 3 x}

= e^{2 x} \cdot 2 - 3 e^{- 3 x}

\frac{d x}{d y} = x (1 - x)

x \to 0 lim ((1 + x^{2})^{\frac{1}{x}})

4 \frac{d ^{2} x}{d t ^{2}} + 7 \frac{d x}{d t} + 15 x = 0

x \to 10 - lim (\frac{- 8}{x - 10})

y = arccos (x) + x

What is the derivative of e^{2x}+e^{-3x} ?
The derivative of e^{2x}+e^{-3x} is e^{2x}*2-3e^{-3x}
What is the first derivative of e^{2x}+e^{-3x} ?
The first derivative of e^{2x}+e^{-3x} is e^{2x}*2-3e^{-3x}