What is the limit as n approaches infinity of-3^{-n} ?

The limit as n approaches infinity of-3^{-n} is 0

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limit as n approaches infinity of-3^{-n}

n \to \infty lim (- 3^{- n})

0

Solution steps

n \to \infty lim (- 3^{- n})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - n \to \infty lim (3^{- n})

Apply exponent rules

= - n \to \infty lim (e^{- n l n (3)})

Apply the Limit Chain Rule:

0

= - 0

Simplify

= 0

\int \frac{1}{x + 1} d x

f (x) = 8 + 4 x^{2} - 2 x^{3}, at x = 2

x^{3} y^{^{'}} = x^{2} y - y^{3}

\int cos^{3} (\frac{x}{13}) d x

x \to 0 lim (x + 6)

What is the limit as n approaches infinity of-3^{-n} ?
The limit as n approaches infinity of-3^{-n} is 0