What is the derivative of y=(9x^4+5x)^3 ?

The derivative of y=(9x^4+5x)^3 is 3(9x^4+5x)^2(36x^3+5)

What is the first derivative of y=(9x^4+5x)^3 ?

The first derivative of y=(9x^4+5x)^3 is 3(9x^4+5x)^2(36x^3+5)

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derivative of

y = (9 x^{4} + 5 x)^{3}

3 (9 x^{4} + 5 x)^{2} (36 x^{3} + 5)

Solution steps

\frac{d}{d x} ((9 x^{4} + 5 x)^{3})

Apply the chain rule:

3 (9 x^{4} + 5 x)^{2} \frac{d}{d x} (9 x^{4} + 5 x)

= 3 (9 x^{4} + 5 x)^{2} \frac{d}{d x} (9 x^{4} + 5 x)

\frac{d}{d x} (9 x^{4} + 5 x) = 36 x^{3} + 5

= 3 (9 x^{4} + 5 x)^{2} (36 x^{3} + 5)

\int e^{8 x + 7} d x

\frac{d x}{d t} = b (1 - x) x

\frac{\partial}{\partial x} (x (x + y)^{2})

\frac{d}{d x} (\frac{4 x ^{3} + 9}{x})

\frac{d}{d t} (sin (ω t + θ))

What is the derivative of y=(9x^4+5x)^3 ?
The derivative of y=(9x^4+5x)^3 is 3(9x^4+5x)^2(36x^3+5)
What is the first derivative of y=(9x^4+5x)^3 ?
The first derivative of y=(9x^4+5x)^3 is 3(9x^4+5x)^2(36x^3+5)