What is the integral from 0 to 1 of (1) ?

The integral from 0 to 1 of (1) is 1

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integral from 0 to 1 of (1)

\int_{0}^{1} (1) d x

1

Solution steps

\int_{0}^{1} 1 d x

Integral of a constant:

\int a d x = a x

= [1 \cdot x]_{0}^{1}

Simplify

= [x]_{0}^{1}

Compute the boundaries:

1

= 1

x e^{x} y^{^{'}} + 2 e^{x} y = 0

\int 9 - 16 x^{2} d x

\int (\frac{1}{x ^{2} - 9}) d x

x, - x + 6, 0

\frac{\partial}{\partial x} ((x^{2} + 9 x - 4 y)^{6})