What is the integral from 4 to 9 of sqrt(4x) ?

The integral from 4 to 9 of sqrt(4x) is 76/3

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integral from 4 to 9 of sqrt(4x)

\int_{4}^{9} 4 x d x

\frac{76}{3}

Decimal Notation

25.33333 \dots

Solution steps

\int_{4}^{9} 4 x d x

Simplify

4 x : 2 x

= \int_{4}^{9} 2 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{4}^{9} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{4}^{9}

= 2 [\frac{2}{3} x^{\frac{3}{2}}]_{4}^{9}

Compute the boundaries:

\frac{38}{3}

= 2 \cdot \frac{38}{3}

Simplify

= \frac{76}{3}

\frac{\partial}{\partial x} (x^{2} \frac{1}{a ^{2}})

\int \frac{13 x ^{3}}{7 + x ^{2}} d x

\int (3 x^{2} + 4 x - 4) d x

\frac{d}{d x} (csc (6 x))

2 x^{4} - 10 x^{2}

What is the integral from 4 to 9 of sqrt(4x) ?
The integral from 4 to 9 of sqrt(4x) is 76/3