What is the limit as x approaches pi-of ln(sin(x)) ?

The limit as x approaches pi-of ln(sin(x)) is -infinity

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limit as x approaches pi-of ln(sin(x))

x \to π - lim (ln (sin (x)))

- \infty

Solution steps

x \to π - lim (ln (sin (x)))

Apply the Limit Chain Rule:

- \infty

= - \infty

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(- 2, 5), (2, - 7)

x \to 2 - lim (\frac{- 2}{x ^{2} - 4})

What is the limit as x approaches pi-of ln(sin(x)) ?
The limit as x approaches pi-of ln(sin(x)) is -infinity