What is (\partial)/(\partial x)(9y^2-1x^2) ?

The answer to (\partial)/(\partial x)(9y^2-1x^2) is -2x

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(\partial)/(\partial x)(9y^2-1x^2)

\frac{\partial}{\partial x} (9 y^{2} - 1 x^{2})

- 2 x

Solution steps

\frac{\partial}{\partial x} (9 y^{2} - 1 \cdot x^{2})

Simplify

9 y^{2} - 1 \cdot x^{2} : 9 y^{2} - x^{2}

= \frac{\partial}{\partial x} (9 y^{2} - x^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (9 y^{2}) - \frac{\partial}{\partial x} (x^{2})

\frac{\partial}{\partial x} (9 y^{2}) = 0

\frac{\partial}{\partial x} (x^{2}) = 2 x

= 0 - 2 x

Simplify

= - 2 x

\int \frac{1}{( a + b x ) x} d x

y^{^{''}} - 4 y^{^{'}} + 2 y = 0

f (x) = \frac{6 - sec ( x )}{tan ( x )}

\frac{d}{d x} (3 csc^{2} (x))

\int x (1 + x)^{\frac{1}{4}} d x

What is (\partial)/(\partial x)(9y^2-1x^2) ?
The answer to (\partial)/(\partial x)(9y^2-1x^2) is -2x