What is the derivative of f(x)=(x+1)/(x-2) ?

The derivative of f(x)=(x+1)/(x-2) is -3/((x-2)^2)

What is the first derivative of f(x)=(x+1)/(x-2) ?

The first derivative of f(x)=(x+1)/(x-2) is -3/((x-2)^2)

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derivative of

f (x) = \frac{x + 1}{x - 2}

- \frac{3}{( x - 2 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x + 1}{x - 2})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x + 1 ) ( x - 2 ) - \frac{d}{d x} ( x - 2 ) ( x + 1 )}{( x - 2 ) ^{2}}

\frac{d}{d x} (x + 1) = 1

\frac{d}{d x} (x - 2) = 1

= \frac{1 \cdot ( x - 2 ) - 1 \cdot ( x + 1 )}{( x - 2 ) ^{2}}

Simplify

\frac{1 \cdot ( x - 2 ) - 1 \cdot ( x + 1 )}{( x - 2 ) ^{2}} : - \frac{3}{( x - 2 ) ^{2}}

= - \frac{3}{( x - 2 ) ^{2}}

\int 0 d x

x^{4} - 3 x^{3} + 2 x^{2} - x + 1

f (x) = x^{5} cos (2 x)

\int_{- 2}^{3} (x^{3} - 6 x) d x

\int \frac{x}{x ^{2} sin ^{2} ( ln ( x ) )} d x

What is the derivative of f(x)=(x+1)/(x-2) ?
The derivative of f(x)=(x+1)/(x-2) is -3/((x-2)^2)
What is the first derivative of f(x)=(x+1)/(x-2) ?
The first derivative of f(x)=(x+1)/(x-2) is -3/((x-2)^2)