What is the derivative of (x^2/(x-9)) ?

The derivative of (x^2/(x-9)) is (x^2-18x)/((x-9)^2)

What is the first derivative of (x^2/(x-9)) ?

The first derivative of (x^2/(x-9)) is (x^2-18x)/((x-9)^2)

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\frac{d}{d x} (\frac{x ^{2}}{x - 9})

\frac{x ^{2} - 18 x}{( x - 9 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{x - 9})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) ( x - 9 ) - \frac{d}{d x} ( x - 9 ) x ^{2}}{( x - 9 ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x - 9) = 1

= \frac{2 x ( x - 9 ) - 1 \cdot x ^{2}}{( x - 9 ) ^{2}}

Simplify

\frac{2 x ( x - 9 ) - 1 \cdot x ^{2}}{( x - 9 ) ^{2}} : \frac{x ^{2} - 18 x}{( x - 9 ) ^{2}}

= \frac{x ^{2} - 18 x}{( x - 9 ) ^{2}}

(- 8, 9), (- 2, - 3)

x y + y^{^{'}} = 100 x

\int_{- 3}^{1} 2 x + 2 d x

f (x) = x^{3} - 3 x^{2} + 1

\int (1 + x^{5})^{3} 5 x^{4} d x

What is the derivative of (x^2/(x-9)) ?
The derivative of (x^2/(x-9)) is (x^2-18x)/((x-9)^2)
What is the first derivative of (x^2/(x-9)) ?
The first derivative of (x^2/(x-9)) is (x^2-18x)/((x-9)^2)