What is the limit as x approaches 1 of+(4/(2x-2)) ?

The limit as x approaches 1 of+(4/(2x-2)) is diverges

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limit as x approaches 1 of+(4/(2x-2))

x \to 1 lim (+ (\frac{4}{2 x - 2}))

diverges

Solution steps

x \to 1 lim (\frac{4}{2 x - 2})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (\frac{4}{2 x - 2}) = \infty

x \to 1 - lim (\frac{4}{2 x - 2}) = - \infty

= diverges

5 (x^{3} - x)^{4}

x \to 0 + lim (x ln (tan (2 x)))

\int x (2 sec^{2} (x) + tan^{2} (x)) d x

f (x) = 2 x^{3} + 3 x^{2} - 12 x + 4

x \to \frac{π}{4} lim (\frac{sin ( x )}{x})

What is the limit as x approaches 1 of+(4/(2x-2)) ?
The limit as x approaches 1 of+(4/(2x-2)) is diverges