What is the solution for e^{y^2}dx+x^2ydy=0 ?

The solution for e^{y^2}dx+x^2ydy=0 is y=sqrt(-ln(-2/x-c_{1))},y=-sqrt(-ln(-2/x-c_{1))}

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e^{y^2}dx+x^2ydy=0

e^{y^{2}} d x + x^{2} y d y = 0

y = - ln (- \frac{2}{x} - c_{1}), y = - - ln (- \frac{2}{x} - c_{1})

Solution steps

e^{y^{2}} d x + x^{2} y d y = 0

Solve separable ODE:

y = - ln (- \frac{2}{x} - c_{1}), y = - - ln (- \frac{2}{x} - c_{1})

y = - ln (- \frac{2}{x} - c_{1}), y = - - ln (- \frac{2}{x} - c_{1})

\frac{d ^{2} y}{d x ^{2}} - 2 \frac{d y}{d x} + y = e^{x}

\int \frac{25 - 16 x ^{2}}{x} d x

\frac{\partial}{\partial x} (\frac{y}{y ^{2} + x ^{2}})

\int_{- 1}^{1} x cos (nπ x) d x

What is the solution for e^{y^2}dx+x^2ydy=0 ?
The solution for e^{y^2}dx+x^2ydy=0 is y=sqrt(-ln(-2/x-c_{1))},y=-sqrt(-ln(-2/x-c_{1))}