What is the integral of 1/(sqrt(1-v^2)) ?

The integral of 1/(sqrt(1-v^2)) is arcsin(v)+C

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integral of 1/(sqrt(1-v^2))

\int \frac{1}{1 - v ^{2}} d v

arcsin (v) + C

Solution steps

\int \frac{1}{1 - v ^{2}} d v

Use the common integral:

\int \frac{1}{1 - v ^{2}} d v = arcsin (v)

= arcsin (v)

Add a constant to the solution

= arcsin (v) + C

\int (x - 2)^{2} d x

\frac{d}{d x} (\frac{1 - ln ( x )}{1 + ln ( x )})

\frac{5}{x}, at x = a

\int \frac{1}{x ^{3} ( ( x ^{2} - 9 ) )} d x

\frac{d}{d x} ((e^{x} - 1)^{2})

What is the integral of 1/(sqrt(1-v^2)) ?
The integral of 1/(sqrt(1-v^2)) is arcsin(v)+C