What is the d/(dθ)(-sin(θ)) ?

The d/(dθ)(-sin(θ)) is -cos(θ)

What is the first d/(dθ)(-sin(θ)) ?

The first d/(dθ)(-sin(θ)) is -cos(θ)

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\frac{d}{d θ} (- sin (θ))

- cos (θ)

Solution steps

\frac{d}{d θ} (- sin (θ))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d θ} (sin (θ))

Apply the common derivative:

\frac{d}{d θ} (sin (θ)) = cos (θ)

= - cos (θ)

y = 2 x^{3} - x^{2} + 3, (2, 15)

\frac{1}{2} y^{^{''}} + 2 y = 2 tan (2 t) - \frac{1}{2} e^{3 t}

(6, - 6), (8, 8)

x^{3} + y^{3} - 6 x y = 0, (\frac{4}{3}, \frac{8}{3})

\frac{\partial}{\partial x} (e^{x^{2} y} + x y^{3})