What is the integral of 1/(X^2)DX ?

The integral of 1/(X^2)DX is Dln|X|+C

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integral of 1/(X^2)DX

\int \frac{1}{X ^{2}} D X d X

D ln ∣ X ∣ + C

Solution steps

\int \frac{1}{X ^{2}} D X d X

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= D \cdot \int \frac{1}{X ^{2}} X d X

Simplify

\frac{1}{X ^{2}} X : \frac{1}{X}

= D \cdot \int \frac{1}{X} d X

Use the common integral:

\int \frac{1}{X} d X = ln (∣ X ∣)

= D ln ∣ X ∣

Add a constant to the solution

= D ln ∣ X ∣ + C

n = 0 \sum \infty 20000

g (x) = \frac{9 ln ( x )}{4 x + 5}

\int \frac{1}{( 2 x + 1 ) ^{3}} d x

y = 10 csc (9 x^{4} - 9 x + 4)

\frac{1}{s [ ( s + 2 ) ^{2} + 1 ]}