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Popular >

y^'-y=4

Solution

y^{^{'}} - y = 4

Solution

y = e^{t + c_{1}} - 4

Solution steps

y^{'} (t) - y = 4

Solve separable ODE:

y = e^{t + c_{1}} - 4

y = e^{t + c_{1}} - 4

Popular Examples

integral of (x^2-6x)

\int (x^{2} - 6 x) d x

limit as x approaches 0 of h(x)

x \to 0 lim (h (x))

integral of (sin(x)cos(x))/(1+sin^2(x))

\int \frac{sin ( x ) cos ( x )}{1 + sin ^{2} ( x )} d x

derivative of e^{5x}

\frac{d}{d x} (e^{5 x})

y^{^{''}} = y

Frequently Asked Questions (FAQ)

What is the solution for y^'-y=4 ?
The solution for y^'-y=4 is y=e^{t+c_{1}}-4