What is the derivative of x^3-2x^2+x ?

The derivative of x^3-2x^2+x is 3x^2-4x+1

What is the first derivative of x^3-2x^2+x ?

The first derivative of x^3-2x^2+x is 3x^2-4x+1

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\frac{d}{d x} (x^{3} - 2 x^{2} + x)

3 x^{2} - 4 x + 1

Solution steps

\frac{d}{d x} (x^{3} - 2 x^{2} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (2 x^{2}) + \frac{d x}{d x}

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d x}{d x} = 1

= 3 x^{2} - 4 x + 1

x \to 0 + lim (x^{x^{4}})

f (x) = \frac{1}{3} x^{3} - \frac{3}{2} x^{2} - 4 x

\frac{\partial}{\partial x} (1 + 2 x y)

\frac{s}{( s + 2 ) ^{2} + 1}

\int 7 x^{5} + 6 x^{4} - 3 x^{3} - 9 x + 5 d x

What is the derivative of x^3-2x^2+x ?
The derivative of x^3-2x^2+x is 3x^2-4x+1
What is the first derivative of x^3-2x^2+x ?
The first derivative of x^3-2x^2+x is 3x^2-4x+1