What is the tangent of f(x)=(8x)/(x^2+1),(1,4) ?

The tangent of f(x)=(8x)/(x^2+1),(1,4) is y=4

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tangent of f(x)=(8x)/(x^2+1),(1,4)

tangent of

f (x) = \frac{8 x}{x ^{2} + 1}, (1, 4)

y = 4

Solution steps

Find the slope of

f (x) = \frac{8 x}{x ^{2} + 1} : \frac{df ( x )}{d x} = \frac{8 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

Compute the slope of

f (x) = \frac{8 x}{x ^{2} + 1}

(1, 4) : m = 0

Find the line with slope m=

0

and passing through

(1, 4) : y = 4

y = 4

\frac{d}{d x} (\frac{4 x}{3 - tan ( x )})

x \to 0 lim (sin (a x))

\frac{10 s}{s ^{2} + 16}

\int \frac{1}{sin ^{2} ( 2 x + \frac{π}{4} )} d x

\int_{2}^{\infty} \frac{1}{v ^{2} + 5 v - 6} d v

What is the tangent of f(x)=(8x)/(x^2+1),(1,4) ?
The tangent of f(x)=(8x)/(x^2+1),(1,4) is y=4