What is the derivative of (8x-x^2)^3 ?

The derivative of (8x-x^2)^3 is 3(8x-x^2)^2(8-2x)

What is the first derivative of (8x-x^2)^3 ?

The first derivative of (8x-x^2)^3 is 3(8x-x^2)^2(8-2x)

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derivative of

(8 x - x^{2})^{3}

3 (8 x - x^{2})^{2} (8 - 2 x)

Solution steps

\frac{d}{d x} ((8 x - x^{2})^{3})

Apply the chain rule:

3 (8 x - x^{2})^{2} \frac{d}{d x} (8 x - x^{2})

= 3 (8 x - x^{2})^{2} \frac{d}{d x} (8 x - x^{2})

\frac{d}{d x} (8 x - x^{2}) = 8 - 2 x

= 3 (8 x - x^{2})^{2} (8 - 2 x)

e^{t} \cdot cos (t) + j \cdot e^{t} \cdot sin (t)

e^{x} d x = 2 y d y

\frac{d}{d y} (x + 3 y^{\frac{1}{3}})

\frac{\partial}{\partial y} (2 x y^{4})

f (x) = (x)^{(3)} e^{(3 x)}

What is the derivative of (8x-x^2)^3 ?
The derivative of (8x-x^2)^3 is 3(8x-x^2)^2(8-2x)
What is the first derivative of (8x-x^2)^3 ?
The first derivative of (8x-x^2)^3 is 3(8x-x^2)^2(8-2x)