What is the first derivative of 2t^4 ?

The first derivative of 2t^4 is 8t^3

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derivative of 2t^4

derivative of

2 t^{4}

8 t^{3}

Solution steps

\frac{d}{d t} (2 t^{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (t^{4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 4 t^{4 - 1}

Simplify

= 8 t^{3}

\int \frac{1}{x x ^{2} + 4} d x

f (x) = \frac{x}{9 - x}

\int 9 x 1 - x^{4} d x

\frac{\partial}{\partial x} (ln (x^{2} + y^{2} + 8))

\frac{d}{d x} (\frac{3}{x ^{6}})