What is the integral of (ln(x))/((1+ln(x))^2) ?

The integral of (ln(x))/((1+ln(x))^2) is -(xln(x))/(1+ln(x))+x+C

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integral of (ln(x))/((1+ln(x))^2)

\int \frac{ln ( x )}{( 1 + ln ( x ) ) ^{2}} d x

- \frac{x ln ( x )}{1 + ln ( x )} + x + C

Solution steps

\int \frac{ln ( x )}{( 1 + ln ( x ) ) ^{2}} d x

Apply u-substitution

: \int \frac{e ^{u} u}{( 1 + u ) ^{2}} d u

= \int \frac{e ^{u} u}{( 1 + u ) ^{2}} d u

Apply Integration By Parts

: - \frac{e ^{u} u}{1 + u} - \int - e^{u} d u

= - \frac{e ^{u} u}{1 + u} - \int - e^{u} d u

\int - e^{u} d u = - e^{u}

= - \frac{e ^{u} u}{1 + u} - (- e^{u})

Substitute back

u = ln (x)

= - \frac{e ^{l n (x)} ln ( x )}{1 + ln ( x )} - (- e^{l n (x)})

Simplify

- \frac{e ^{l n (x)} ln ( x )}{1 + ln ( x )} - (- e^{l n (x)}) : - \frac{x ln ( x )}{1 + ln ( x )} + x

= - \frac{x ln ( x )}{1 + ln ( x )} + x

Add a constant to the solution

= - \frac{x ln ( x )}{1 + ln ( x )} + x + C

x \to 0 - lim (\frac{∣ 2 x ∣}{x})

\frac{\partial}{\partial y} (\frac{x}{x ^{2} + y ^{2} + 1})

x \to 7 lim (x^{2} - 49)

\int \frac{200}{1 + x} d x

\frac{1 + 5 s ^{2}}{s ^{2} ( s - 9 )}

What is the integral of (ln(x))/((1+ln(x))^2) ?
The integral of (ln(x))/((1+ln(x))^2) is -(xln(x))/(1+ln(x))+x+C