What is (\partial)/(\partial x)(x^2-4y^2) ?

The answer to (\partial)/(\partial x)(x^2-4y^2) is 2x

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(\partial)/(\partial x)(x^2-4y^2)

\frac{\partial}{\partial x} (x^{2} - 4 y^{2})

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} - 4 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (4 y^{2})

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (4 y^{2}) = 0

= 2 x - 0

Simplify

= 2 x

x \to + 1 lim (x^{3} - 1)

\frac{d ^{2} y}{d x ^{2}} - b y = 0

100 x - \frac{d y}{d x} = x y

cot (x)

f (x) = \frac{7 x}{2 ^{x}}, at x = 2

What is (\partial)/(\partial x)(x^2-4y^2) ?
The answer to (\partial)/(\partial x)(x^2-4y^2) is 2x