What is the limit as x approaches 4+of sqrt(x^2-16) ?

The limit as x approaches 4+of sqrt(x^2-16) is 0

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limit as x approaches 4+of sqrt(x^2-16)

x \to 4 + lim (x^{2} - 16)

0

Solution steps

x \to 4 + lim (x^{2} - 16)

Plug in the value

x = 4

= 4^{2} - 16

Simplify

= 0

x \to 0 lim (\frac{1 ^{2 x} - 1}{x})

ln (c)

\int \frac{z}{z ^{2} + z - 1} d z

f (x) = sec (3 x)

\frac{\partial}{\partial y} (\frac{y}{( x ^{2} + y ^{2} ) ^{\frac{3}{2}}})

What is the limit as x approaches 4+of sqrt(x^2-16) ?
The limit as x approaches 4+of sqrt(x^2-16) is 0