What is the integral of x^5cos(x^3) ?

The integral of x^5cos(x^3) is 1/3 (x^3sin(x^3)+cos(x^3))+C

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integral of x^5cos(x^3)

\int x^{5} cos (x^{3}) d x

\frac{1}{3} (x^{3} sin (x^{3}) + cos (x^{3})) + C

Solution steps

\int x^{5} cos (x^{3}) d x

Apply u-substitution

: \int \frac{u cos ( u )}{3} d u

= \int \frac{u cos ( u )}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int u cos (u) d u

Apply Integration By Parts

: u sin (u) - \int sin (u) d u

= \frac{1}{3} (u sin (u) - \int sin (u) d u)

\int sin (u) d u = - cos (u)

= \frac{1}{3} (u sin (u) - (- cos (u)))

Substitute back

u = x^{3}

= \frac{1}{3} (x^{3} sin (x^{3}) - (- cos (x^{3})))

Simplify

= \frac{1}{3} (x^{3} sin (x^{3}) + cos (x^{3}))

Add a constant to the solution

= \frac{1}{3} (x^{3} sin (x^{3}) + cos (x^{3})) + C

\frac{d}{d x} (2 x^{2} + y^{3})

\int sin (2 x) cos (7 x) d x

\int 5 tan^{5} (x) sec^{4} (x) d x

\int_{6}^{8} \frac{12}{( x - 6 ) ^{3}} d x

y = 6 x^{2} - 2 x, y = x^{3} - 6 x + 2

What is the integral of x^5cos(x^3) ?
The integral of x^5cos(x^3) is 1/3 (x^3sin(x^3)+cos(x^3))+C