What is (\partial ^2)/(\partial y\partial x)((xy)/(x-y)) ?

The answer to (\partial ^2)/(\partial y\partial x)((xy)/(x-y)) is -(2xy)/((x-y)^3)

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(\partial ^2)/(\partial y\partial x)((xy)/(x-y))

\frac{\partial ^{2}}{\partial y \partial x} (\frac{x y}{x - y})

- \frac{2 x y}{( x - y ) ^{3}}

Solution steps

\frac{\partial ^{2}}{\partial y \partial x} (\frac{x y}{x - y})

\frac{\partial}{\partial y} (\frac{x y}{x - y}) = \frac{x ^{2}}{( x - y ) ^{2}}

= \frac{\partial}{\partial x} (\frac{x ^{2}}{( x - y ) ^{2}})

\frac{\partial}{\partial x} (\frac{x ^{2}}{( x - y ) ^{2}}) = - \frac{2 x y}{( x - y ) ^{3}}

= - \frac{2 x y}{( x - y ) ^{3}}

\int \frac{x ^{2} - 36}{x ^{2}} d x

\int \frac{1}{16 + x ^{2}} d x

x \to 0 + lim (- \frac{3 ln ( x )}{x})

y = 4 sec (x) - 8 cos (x)

\int \frac{2 ^{x}}{ln ( 2 )} d x

What is (\partial ^2)/(\partial y\partial x)((xy)/(x-y)) ?
The answer to (\partial ^2)/(\partial y\partial x)((xy)/(x-y)) is -(2xy)/((x-y)^3)