What is the derivative of x^3+7x ?

The derivative of x^3+7x is 3x^2+7

What is the first derivative of x^3+7x ?

The first derivative of x^3+7x is 3x^2+7

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\frac{d}{d x} (x^{3} + 7 x)

3 x^{2} + 7

Solution steps

\frac{d}{d x} (x^{3} + 7 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (7 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (7 x) = 7

= 3 x^{2} + 7

\int_{0}^{1} \frac{1}{1 + x ^{2}} d x

\int e^{1 - 3 x} d x

x \to \infty lim (x^{1})

y^{^{''}} + 2 y = e x + x^{3}

What is the derivative of x^3+7x ?
The derivative of x^3+7x is 3x^2+7
What is the first derivative of x^3+7x ?
The first derivative of x^3+7x is 3x^2+7