What is (\partial)/(\partial u)(2u+v) ?

The answer to (\partial)/(\partial u)(2u+v) is 2

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(\partial)/(\partial u)(2u+v)

\frac{\partial}{\partial u} (2 u + v)

2

Solution steps

\frac{\partial}{\partial u} (2 u + v)

Treat

v

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial u} (2 u) + \frac{\partial}{\partial u} (v)

\frac{\partial}{\partial u} (2 u) = 2

\frac{\partial}{\partial u} (v) = 0

= 2 + 0

Simplify

= 2

\frac{\partial}{\partial x} (tan (x y))

y = e^{t a n (x)}

x \to 0 lim (\frac{cos ( x )}{96})

\frac{d y}{d t} + 0.3 t y = 9 t

What is (\partial)/(\partial u)(2u+v) ?
The answer to (\partial)/(\partial u)(2u+v) is 2