What is (\partial)/(\partial u)(sin(v)cos(u)) ?

The answer to (\partial)/(\partial u)(sin(v)cos(u)) is -sin(v)sin(u)

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(\partial)/(\partial u)(sin(v)cos(u))

\frac{\partial}{\partial u} (sin (v) cos (u))

- sin (v) sin (u)

Solution steps

\frac{\partial}{\partial u} (sin (v) cos (u))

Treat

v

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (v) \frac{\partial}{\partial u} (cos (u))

Apply the common derivative:

\frac{\partial}{\partial u} (cos (u)) = - sin (u)

= sin (v) (- sin (u))

Simplify

= - sin (v) sin (u)

\frac{1}{s ^{4} + s ^{3}}

x \to - \infty lim (\frac{8 x ^{2} + 7 x ^{\frac{1}{3}}}{16 x ^{4} + 6})

(cos (t))^{^{'}}

\frac{d}{d x} ((x e^{2 x} + x^{3})^{6})

What is (\partial)/(\partial u)(sin(v)cos(u)) ?
The answer to (\partial)/(\partial u)(sin(v)cos(u)) is -sin(v)sin(u)