What is the tangent of y=x^2-2x-2,(2,-2) ?

The tangent of y=x^2-2x-2,(2,-2) is y=2x-6

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tangent of y=x^2-2x-2,(2,-2)

tangent of

y = x^{2} - 2 x - 2, (2, - 2)

y = 2 x - 6

Solution steps

Find the slope of

y = x^{2} - 2 x - 2 : \frac{d y}{d x} = 2 x - 2

Compute the slope of

y = x^{2} - 2 x - 2

(2, - 2) : m = 2

Find the line with slope m=

2

and passing through

(2, - 2) : y = 2 x - 6

y = 2 x - 6

\frac{1}{s ^{2} - 6 s + 9}

\int 22 arctan (x) d x

cos (x - 7 x)

n = 0 \sum \infty 6^{n} x^{n}

n = 1 \sum \infty \frac{4}{n}

What is the tangent of y=x^2-2x-2,(2,-2) ?
The tangent of y=x^2-2x-2,(2,-2) is y=2x-6