What is the integral of 2/(x^{2/3)} ?

The integral of 2/(x^{2/3)} is 6x^{1/3}+C

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integral of 2/(x^{2/3)}

\int \frac{2}{x ^{\frac{2}{3}}} d x

6 x^{\frac{1}{3}} + C

Solution steps

\int \frac{2}{x ^{\frac{2}{3}}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{1}{x ^{\frac{2}{3}}} d x

Apply the Power Rule

: 3 x^{\frac{1}{3}}

= 2 \cdot 3 x^{\frac{1}{3}}

Simplify

= 6 x^{\frac{1}{3}}

Add a constant to the solution

= 6 x^{\frac{1}{3}} + C

2 y \cdot \frac{d y}{d x} = x (y^{2} + 1)

\frac{d}{d x} (in (x^{2} - 5))

y^{^{'}} = 1 - e^{x - y + 8}

\frac{5}{8 s}

x \to 3 + lim ((x^{2} - 9)^{x - 3})