What is the derivative of 4x\sqrt[3]{x} ?

The derivative of 4x\sqrt[3]{x} is (16\sqrt[3]{x})/3

What is the first derivative of 4x\sqrt[3]{x} ?

The first derivative of 4x\sqrt[3]{x} is (16\sqrt[3]{x})/3

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Solution steps

Simplify

= \frac{d}{d x} (4 x^{\frac{4}{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (x^{\frac{4}{3}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 \cdot \frac{4}{3} x^{\frac{4}{3} - 1}

Simplify

\int 1 - e^{2 x} d x

1 - x^{2}, 4 - 4 x

\int (3 x + 5)^{4} d x

\frac{d}{d x} (\frac{x ^{3} + 2}{3})

x^{2}, x^{5}

What is the derivative of 4x\sqrt[3]{x} ?
The derivative of 4x\sqrt[3]{x} is (16\sqrt[3]{x})/3
What is the first derivative of 4x\sqrt[3]{x} ?
The first derivative of 4x\sqrt[3]{x} is (16\sqrt[3]{x})/3