What is the solution for (xcsc(y/x)-y)dx+xdy=0 ?

The solution for (xcsc(y/x)-y)dx+xdy=0 is y=arccos(ln(x)-c_{1})x+2pinx,y=-arccos(ln(x)-c_{1})x+2pinx

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(xcsc(y/x)-y)dx+xdy=0

(x csc (\frac{y}{x}) - y) d x + x d y = 0

y = arccos (ln (x) - c_{1}) x + 2 πn x, y = - arccos (ln (x) - c_{1}) x + 2 πn x

Solution steps

(x csc (\frac{y}{x}) - y) d x + x d y = 0

Solve using substitution:

y = arccos (ln (x) - c_{1}) x + 2 πn x, y = - arccos (ln (x) - c_{1}) x + 2 πn x

y = arccos (ln (x) - c_{1}) x + 2 πn x, y = - arccos (ln (x) - c_{1}) x + 2 πn x

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What is the solution for (xcsc(y/x)-y)dx+xdy=0 ?
The solution for (xcsc(y/x)-y)dx+xdy=0 is y=arccos(ln(x)-c_{1})x+2pinx,y=-arccos(ln(x)-c_{1})x+2pinx