What is (\partial)/(\partial v)(sin(u)cos(v)) ?

The answer to (\partial)/(\partial v)(sin(u)cos(v)) is -sin(u)sin(v)

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(\partial)/(\partial v)(sin(u)cos(v))

\frac{\partial}{\partial v} (sin (u) cos (v))

- sin (u) sin (v)

Solution steps

\frac{\partial}{\partial v} (sin (u) cos (v))

Treat

u

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (u) \frac{\partial}{\partial v} (cos (v))

Apply the common derivative:

\frac{\partial}{\partial v} (cos (v)) = - sin (v)

= sin (u) (- sin (v))

Simplify

= - sin (u) sin (v)

y^{^{'}} = 5 y - x y

y^{^{''}} + 8 y^{^{'}} + 25 y = - 208 \cdot sin (3 x)

x \to 3 lim (3 - ∣ x - 3 ∣)

\int \frac{5 ( x - 3 ) ^{2}}{x x} d x

f (x) = \frac{3}{5} x^{15}

What is (\partial)/(\partial v)(sin(u)cos(v)) ?
The answer to (\partial)/(\partial v)(sin(u)cos(v)) is -sin(u)sin(v)