What is the derivative of 2x-2/(x^3) ?

The derivative of 2x-2/(x^3) is 2+6/(x^4)

What is the first derivative of 2x-2/(x^3) ?

The first derivative of 2x-2/(x^3) is 2+6/(x^4)

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\frac{d}{d x} (2 x - \frac{2}{x ^{3}})

2 + \frac{6}{x ^{4}}

Solution steps

\frac{d}{d x} (2 x - \frac{2}{x ^{3}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (\frac{2}{x ^{3}})

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (\frac{2}{x ^{3}}) = - \frac{6}{x ^{4}}

= 2 - (- \frac{6}{x ^{4}})

Simplify

= 2 + \frac{6}{x ^{4}}

\int \frac{1 + cos ( x )}{( x + sin ( x ) ) ^{2}} d x

\frac{e ^{x}}{2 x + 1}

y = x^{6} cos (x)

e^{x} (y^{3} + x y^{3} + 1) d x + 3 y^{2} (x e^{x} - 6) d y = 0

What is the derivative of 2x-2/(x^3) ?
The derivative of 2x-2/(x^3) is 2+6/(x^4)
What is the first derivative of 2x-2/(x^3) ?
The first derivative of 2x-2/(x^3) is 2+6/(x^4)