What is the limit as h approaches 0 of cos(pi/2) ?

The limit as h approaches 0 of cos(pi/2) is 0

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limit as h approaches 0 of cos(pi/2)

h \to 0 lim (cos (\frac{π}{2}))

0

Solution steps

h \to 0 lim (cos (\frac{π}{2}))

x \to a lim c = c

= cos (\frac{π}{2})

Use the following trivial identity:

cos (\frac{π}{2}) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 0

\int_{0}^{4} e^{x} d x

\frac{d}{d x} (- ln (2 x))

\frac{d}{d x} (x ln (x^{10}))

\int x (x^{2} - 3) d x

\frac{d}{d x} (- 25 (\frac{x}{x ^{2} + 1}))

What is the limit as h approaches 0 of cos(pi/2) ?
The limit as h approaches 0 of cos(pi/2) is 0